C# – Binding a WPF DataGrid to a DataTable

bindingc++datagridwpf

I'm not good at English because I'm not a native speaker. I apologize if I've made mistakes in the language 🙂

I'm new in C# and WPF and I'm trying to bind a WPF DataGrid to a DataTable in TwoWay. Now when I edit the values in the DataGrid, data in the DataTable change correctly. When I try to fill the DataTable with the following code:

OleDbDataAdapter adapter = new OleDbDataAdapter("a query", (a connection));
adapter.Fill(dataTable);

the code works and the DataGrid seems all right. But when I try this:

dataTable.Rows[0][1] = (some object);

the display value doesn't change. I try to check the values in the DataGrid in the following way:

MessageBox.Show((SomeDataGrid.Items[0] as DataRowView).Row[1].ToString());

and it turns out no problem. I'm wondering why the display values are like this.

Here's my DataGrid.CellStyle in XAML:

<DataGrid.CellStyle>
    <Style TargetType="DataGridCell">
        <Setter Property="Template">
            <Setter.Value>
                <ControlTemplate TargetType="DataGridCell">
                    <Grid HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Background="{TemplateBinding Background}">
                        <DataGridDetailsPresenter HorizontalAlignment="Stretch" VerticalAlignment="Center" Content="{TemplateBinding Content}"/>
                    </Grid>
                </ControlTemplate>
            </Setter.Value>
        </Setter>
        <Style.Triggers>
            <!-- triggers -->
        </Style.Triggers>
    </Style>
</DataGrid.CellStyle>

I've been stuck on this problem for several days. Thanks for any help!

Best Solution

I am not very sure if this solution will work but it is worth a try.

Instead of binding your DataGrid to a DataTable, try binding it to a DataView . You can convert your DataTable to a DataView using DefaultView property like

DataTable dt = new DataTable();
DataView dv = dt.DefaultView;

On binding with DataView your notification to changes in data should work both ways.

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