C# – new ActionResult that can render the view generated and send contents via email

asp.net-mvcc++

I was wondering if it were possible to write a file FileResult that worked something like this.

public ActionResult Generate(int id)
{
    //Fill Model
    string ViewName = "template1";    

    return new FileResult(ViewName, @"c:\save"+ id +".txt");
}

where it would take the model, and combine it with the view to give you the output that would normally be displayed to the screen but instead just save it with the filename specified.

Note: This file will be saved on the webserver

Best Solution

I don't think it is possible. You can specify the filename and the mime type but that is it. Imagine the security vulnerability caused by what you are proposing.

Related Solutions

C# – How to find the method that called the current method

Try this:

using System.Diagnostics;
// Get call stack
StackTrace stackTrace = new StackTrace(); 
// Get calling method name
Console.WriteLine(stackTrace.GetFrame(1).GetMethod().Name);

one-liner:

(new System.Diagnostics.StackTrace()).GetFrame(1).GetMethod().Name

It is from Get Calling Method using Reflection [C#].

C# – How to return the current action in an ASP.NET MVC view

In the RC you can also extract route data like the action method name like this

ViewContext.Controller.ValueProvider["action"].RawValue
ViewContext.Controller.ValueProvider["controller"].RawValue
ViewContext.Controller.ValueProvider["id"].RawValue

Update for MVC 3

ViewContext.Controller.ValueProvider.GetValue("action").RawValue
ViewContext.Controller.ValueProvider.GetValue("controller").RawValue
ViewContext.Controller.ValueProvider.GetValue("id").RawValue

Update for MVC 4

ViewContext.Controller.RouteData.Values["action"]
ViewContext.Controller.RouteData.Values["controller"]
ViewContext.Controller.RouteData.Values["id"]

Update for MVC 4.5

ViewContext.RouteData.Values["action"]
ViewContext.RouteData.Values["controller"]
ViewContext.RouteData.Values["id"]