How to calculate the coordinates of a arrowhead based on the arrow

algorithm

I have a line that is based on two (x,y) coordinates I know. This line has a starting and an end point. Now I want to add an arrowhead at the end point of the line.

I know that the arrow is an equilateral triangle, and therefore each angle has 60 degrees. Additionally, I know the length of one side, which will be 20. I also no one edge of the triangle (that is the end point of the line).

How can I calculate the other two points of the triangle? I know I should use some trigonometry but how?

P.s. The endpoint of the line should be the arrowhead's tip.

Best Solution

You don't need trig., just some vector arithmetic...

Say the line goes from A to B, with the front vertex of the arrowhead at B. The length of the arrowhead is h = 10(√3) and its half-width is w = 10. We'll denote the unit vector from A to B as U = (B - A)/|B - A| (i.e., the difference divided by the length of the difference), and the unit vector perpendicular to this as V = [-Uy, Ux].

From these quantities, you can calculate the two rear vertices of the arrowhead as B - hU ± wV.

In C++:

struct vec { float x, y; /* … */ };

void arrowhead(vec A, vec B, vec& v1, vec& v2) {
    float h = 10*sqrtf(3), w = 10;
    vec U = (B - A)/(B - A).length();
    vec V = vec(-U.y, U.x);
    v1 = B - h*U + w*V;
    v2 = B - h*U - w*V;
}

If you want to specify different angles, then you will need some trig. to calculate different values of h and w. Assuming you want an arrowhead of length h and tip-angle θ, then w = h tan(θ/2). In practice, however, it's simplest to specify h and w directly.

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