snippet from my xml file:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/util
http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<!-- http://www.springframework.org/schema/aop -->
<!-- http://www.springframework.org/schema/aop/spring-aop.xsd"> -->
<context:component-scan base-package="myPackage" />
after execution I see following message:
WARN [WrapperSimpleAppMain] [XmlBeanDefinitionReader] Ignored XML
validation warning org.xml.sax.SAXParseException; lineNumber: 14;
columnNumber: 80; SchemaLocation: schemaLocation value =
'http://www.springfr amework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.spri ngframework.org/schema/util
http://www.springframework.org/schema/util/spring-util.xsd
http://www.springfra mework.org/schema/context/spring-context-3.1.xsd'
must have even number of URI's.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:198)
How to solve this problem right?
Best Answer
Your
schemaLocation
value should be of the formYou're missing
before
It should therefore be
Note that I've changed the
util
schema to version 3.1. Don't mix and match. Use all the same versions.