Simple ways:
var arr = [1,2,,3,,-3,null,,0,,undefined,4,,4,,5,,6,,,,];
arr.filter(n => n)
// [1, 2, 3, -3, 4, 4, 5, 6]
arr.filter(Number)
// [1, 2, 3, -3, 4, 4, 5, 6]
arr.filter(Boolean)
// [1, 2, 3, -3, 4, 4, 5, 6]
or - (only for single array items of type "text")
['','1','2',3,,'4',,undefined,,,'5'].join('').split('');
// output: ["1","2","3","4","5"]
or - Classic way: simple iteration
var arr = [1,2,null, undefined,3,,3,,,0,,,[],,{},,5,,6,,,,],
len = arr.length, i;
for(i = 0; i < len; i++ )
arr[i] && arr.push(arr[i]); // copy non-empty values to the end of the array
arr.splice(0 , len); // cut the array and leave only the non-empty values
arr // [1,2,3,3,[],Object{},5,6]
via jQuery:
var arr = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
arr = $.grep(arr,function(n){ return n == 0 || n });
arr // [1, 2, 3, 3, 0, 4, 4, 5, 6]
UPDATE - just another fast, cool way (using ES6):
var arr = [1,2,null, undefined,3,,3,,,0,,,4,,4,,5,,6,,,,],
temp = [];
for(let i of arr)
i && temp.push(i); // copy each non-empty value to the 'temp' array
arr = temp;
arr // [1, 2, 3, 3, 4, 4, 5, 6]
Remove empty values
['foo', '',,,'',,null, ' ', 3, true, [], [1], {}, undefined, ()=>{}].filter(String)
// ["foo", null, " ", 3, true, [1], Object {}, undefined, ()=>{}]
Best Answer
You have to tell replace() to repeat the regex:
The g character makes it a "global" match, meaning it repeats the search through the entire string. Read about this, and other RegEx modifiers available in JavaScript here.
If you want to match all whitespace, and not just the literal space character, use
\s
instead:You can also use
.replaceAll
if you're using a sufficiently recent version of JavaScript, but there's not really any reason to for your specific use case, since catching all whitespace requires a regex, and when using a regex with.replaceAll
, it must be global, so you just end up with extra typing: