false, everything else
true. So you could write:
You don't need that
The approach you suggest is not guaranteed to give you the result you're looking for - what if you had a
tbody for example:
You would end up with the following:
I would therefore recommend this approach instead:
You can include anything within the
after() method as long as it's valid HTML, including multiple rows as per the example above.
Update: Revisiting this answer following recent activity with this question. eyelidlessness makes a good comment that there will always be a
tbody in the DOM; this is true, but only if there is at least one row. If you have no rows, there will be no
tbody unless you have specified one yourself.
DaRKoN_ suggests appending to the
tbody rather than adding content after the last
tr. This gets around the issue of having no rows, but still isn't bulletproof as you could theoretically have multiple
tbody elements and the row would get added to each of them.
Weighing everything up, I'm not sure there is a single one-line solution that accounts for every single possible scenario. You will need to make sure the jQuery code tallies with your markup.
I think the safest solution is probably to ensure your
table always includes at least one
tbody in your markup, even if it has no rows. On this basis, you can use the following which will work however many rows you have (and also account for multiple
$('#myTable > tbody:last-child').append('<tr>...</tr><tr>...</tr>');
$.datepicker.noWeekends is a pretty simple bit of code:
Since you're going to have to write up the function for holidays, you can just include this logic in that function too.