In a Bash script, I would like to do something like:
app1 & pidApp1=$! app2 & pidApp2=$1 timeout 60 wait $pidApp1 $pidApp2 kill -9 $pidApp1 $pidApp2
I.e., launch two applications in the background, and give them 60 seconds to complete their work. Then, if they don't finish within that interval, kill them.
Unfortunately, the above does not work, since
timeout is an executable, while
wait is a shell command. I tried changing it to:
timeout 60 bash -c wait $pidApp1 $pidApp2
But this still does not work, since
wait can only be called on a PID launched within the same shell.