Mysql – How to SELECT rows with MAX(Column value), PARTITION by another column in MYSQL

distinctgreatest-n-per-groupmaxmysqlsql

My table is:

id home datetime player resource
1 10 04/03/2009 john 399
2 11 04/03/2009 juliet 244
5 12 04/03/2009 borat 555
3 10 03/03/2009 john 300
4 11 03/03/2009 juliet 200
6 12 03/03/2009 borat 500
7 13 24/12/2008 borat 600
8 13 01/01/2009 borat 700

I need to select each distinct home holding the maximum value of datetime.

Result would be:

id home datetime player resource
1 10 04/03/2009 john 399
2 11 04/03/2009 juliet 244
5 12 04/03/2009 borat 555
8 13 01/01/2009 borat 700

I have tried:

-- 1 ..by the MySQL manual: 

SELECT DISTINCT
  home,
  id,
  datetime AS dt,
  player,
  resource
FROM topten t1
WHERE datetime = (SELECT
  MAX(t2.datetime)
FROM topten t2
GROUP BY home)
GROUP BY datetime
ORDER BY datetime DESC

Doesn't work. Result-set has 130 rows although database holds 187.
Result includes some duplicates of home.

-- 2 ..join

SELECT
  s1.id,
  s1.home,
  s1.datetime,
  s1.player,
  s1.resource
FROM topten s1
JOIN (SELECT
  id,
  MAX(datetime) AS dt
FROM topten
GROUP BY id) AS s2
  ON s1.id = s2.id
ORDER BY datetime 

Nope. Gives all the records.

-- 3 ..something exotic: 

With various results.

Best Solution

You are so close! All you need to do is select BOTH the home and its max date time, then join back to the topten table on BOTH fields:

SELECT tt.*
FROM topten tt
INNER JOIN
    (SELECT home, MAX(datetime) AS MaxDateTime
    FROM topten
    GROUP BY home) groupedtt 
ON tt.home = groupedtt.home 
AND tt.datetime = groupedtt.MaxDateTime