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PHP Session Destroy on Log Out Button

loginlogoutphp

I'm currently working on a site that has a log-in (username and password) – The password protection is done by the operating system within the web server at folder level called a Realm within the OS. For now this will have to do, until we figure out a proper PHP log in system.

The code below, is based on a previous question on the stack overflow.

I'm using 3 files (See code snippets at the bottom).

The process is:
– Click Log In button on index.php
– Enter username and password to access authenticate index file.
– Click log out button, which references the logout.php file – it SHOULD clear the cache and return the user to the top level index.

It doesn't 'destroy the session' in the sense that you're not asked to re-enter the password when prompted to, which is essentially what I want to happen.

My minimal knowledge of php leaves me a little bit stumped here.

index.php (top level file with log in button)

<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Test</title>
</head>
<body>
<a href="authenticate/index.php">Log In Btn</a>
</body>
</html>

authenticate/index.php (This folder is password protected – contains the index file with the log out button which links to the logout.php file)

<?php session_start(); ?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Log out</title>
</head>
<body>
<a href="logout.php">Log Out Btn</a>
</body>
</html>

authenticate/logout.php

<?php   
session_start(); //to ensure you are using same session
session_destroy(); //destroy the session
header("location:/index.php"); //to redirect back to "index.php" after logging out
exit();
?>

Best Solution

The folder being password protected has nothing to do with PHP!

The method being used is called "Basic Authentication". There are no cross-browser ways to "logout" from it, except to ask the user to close and then open their browser...

Here's how you you could do it in PHP instead (fully remove your Apache basic auth in .htaccess or wherever it is first):

login.php:

<?php
session_start();
//change 'valid_username' and 'valid_password' to your desired "correct" username and password
if (! empty($_POST) && $_POST['user'] === 'valid_username' && $_POST['pass'] === 'valid_password')
{
    $_SESSION['logged_in'] = true;
    header('Location: /index.php');
}
else
{
    ?>

    <form method="POST">
    Username: <input name="user" type="text"><br>
    Password: <input name="pass" type="text"><br><br>
    <input type="submit" value="submit">
    </form>

    <?php
}

index.php

<?php
session_start();
if (! empty($_SESSION['logged_in']))
{
    ?>

    <p>here is my super-secret content</p>
    <a href='logout.php'>Click here to log out</a>

    <?php
}
else
{
    echo 'You are not logged in. <a href="login.php">Click here</a> to log in.';
}

logout.php:

<?php
session_start();
session_destroy();
echo 'You have been logged out. <a href="/">Go back</a>';

Obviously this is a very basic implementation. You'd expect the usernames and passwords to be in a database, not as a hardcoded comparison. I'm just trying to give you an idea of how to do the session thing.

Hope this helps you understand what's going on.

Related Solutions

Php – How to prevent SQL injection in PHP

The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create SQL statement with correctly formatted data parts, but if you don't fully understand the details, you should always use prepared statements and parameterized queries. These are SQL statements that are sent to and parsed by the database server separately from any parameters. This way it is impossible for an attacker to inject malicious SQL.

You basically have two options to achieve this:

  1. Using PDO (for any supported database driver):

     $stmt = $pdo->prepare('SELECT * FROM employees WHERE name = :name');
    
     $stmt->execute([ 'name' => $name ]);
    
     foreach ($stmt as $row) {
         // Do something with $row
     }
    
  2. Using MySQLi (for MySQL):

     $stmt = $dbConnection->prepare('SELECT * FROM employees WHERE name = ?');
     $stmt->bind_param('s', $name); // 's' specifies the variable type => 'string'
    
     $stmt->execute();
    
     $result = $stmt->get_result();
     while ($row = $result->fetch_assoc()) {
         // Do something with $row
     }
    

If you're connecting to a database other than MySQL, there is a driver-specific second option that you can refer to (for example, pg_prepare() and pg_execute() for PostgreSQL). PDO is the universal option.


Correctly setting up the connection

Note that when using PDO to access a MySQL database real prepared statements are not used by default. To fix this you have to disable the emulation of prepared statements. An example of creating a connection using PDO is:

$dbConnection = new PDO('mysql:dbname=dbtest;host=127.0.0.1;charset=utf8', 'user', 'password');

$dbConnection->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
$dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);

In the above example the error mode isn't strictly necessary, but it is advised to add it. This way the script will not stop with a Fatal Error when something goes wrong. And it gives the developer the chance to catch any error(s) which are thrown as PDOExceptions.

What is mandatory, however, is the first setAttribute() line, which tells PDO to disable emulated prepared statements and use real prepared statements. This makes sure the statement and the values aren't parsed by PHP before sending it to the MySQL server (giving a possible attacker no chance to inject malicious SQL).

Although you can set the charset in the options of the constructor, it's important to note that 'older' versions of PHP (before 5.3.6) silently ignored the charset parameter in the DSN.


Explanation

The SQL statement you pass to prepare is parsed and compiled by the database server. By specifying parameters (either a ? or a named parameter like :name in the example above) you tell the database engine where you want to filter on. Then when you call execute, the prepared statement is combined with the parameter values you specify.

The important thing here is that the parameter values are combined with the compiled statement, not an SQL string. SQL injection works by tricking the script into including malicious strings when it creates SQL to send to the database. So by sending the actual SQL separately from the parameters, you limit the risk of ending up with something you didn't intend.

Any parameters you send when using a prepared statement will just be treated as strings (although the database engine may do some optimization so parameters may end up as numbers too, of course). In the example above, if the $name variable contains 'Sarah'; DELETE FROM employees the result would simply be a search for the string "'Sarah'; DELETE FROM employees", and you will not end up with an empty table.

Another benefit of using prepared statements is that if you execute the same statement many times in the same session it will only be parsed and compiled once, giving you some speed gains.

Oh, and since you asked about how to do it for an insert, here's an example (using PDO):

$preparedStatement = $db->prepare('INSERT INTO table (column) VALUES (:column)');

$preparedStatement->execute([ 'column' => $unsafeValue ]);

Can prepared statements be used for dynamic queries?

While you can still use prepared statements for the query parameters, the structure of the dynamic query itself cannot be parametrized and certain query features cannot be parametrized.

For these specific scenarios, the best thing to do is use a whitelist filter that restricts the possible values.

// Value whitelist
// $dir can only be 'DESC', otherwise it will be 'ASC'
if (empty($dir) || $dir !== 'DESC') {
   $dir = 'ASC';
}
Php – Deleting an element from an array in PHP

There are different ways to delete an array element, where some are more useful for some specific tasks than others.

Deleting a single array element

If you want to delete just one array element you can use unset() or alternatively \array_splice().

If you know the value and don’t know the key to delete the element you can use \array_search() to get the key. This only works if the element does not occur more than once, since \array_search returns the first hit only.

unset()

Note that when you use unset() the array keys won’t change. If you want to reindex the keys you can use \array_values() after unset(), which will convert all keys to numerically enumerated keys starting from 0.

Code:

$array = [0 => "a", 1 => "b", 2 => "c"];
unset($array[1]);
          // ↑ Key which you want to delete

Output:

[
    [0] => a
    [2] => c
]

\array_splice() method

If you use \array_splice() the keys will automatically be reindexed, but the associative keys won’t change — as opposed to \array_values(), which will convert all keys to numerical keys.

\array_splice() needs the offset, not the key, as the second parameter.

Code:

$array = [0 => "a", 1 => "b", 2 => "c"];
\array_splice($array, 1, 1);
                   // ↑ Offset which you want to delete

Output:

[
    [0] => a
    [1] => c
]

array_splice(), same as unset(), take the array by reference. You don’t assign the return values of those functions back to the array.

Deleting multiple array elements

If you want to delete multiple array elements and don’t want to call unset() or \array_splice() multiple times you can use the functions \array_diff() or \array_diff_key() depending on whether you know the values or the keys of the elements which you want to delete.

\array_diff() method

If you know the values of the array elements which you want to delete, then you can use \array_diff(). As before with unset() it won’t change the keys of the array.

Code:

$array = [0 => "a", 1 => "b", 2 => "c", 3 => "c"];
$array = \array_diff($array, ["a", "c"]);
                          // └────────┘
                          // Array values which you want to delete

Output:

[
    [1] => b
]

\array_diff_key() method

If you know the keys of the elements which you want to delete, then you want to use \array_diff_key(). You have to make sure you pass the keys as keys in the second parameter and not as values. Keys won’t reindex.

Code:

$array = [0 => "a", 1 => "b", 2 => "c"];
$array = \array_diff_key($array, [0 => "xy", "2" => "xy"]);
                               // ↑           ↑
                               // Array keys which you want to delete

Output:

[
    [1] => b
]

If you want to use unset() or \array_splice() to delete multiple elements with the same value you can use \array_keys() to get all the keys for a specific value and then delete all elements.

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