Php – What are the reasons why PHP would echo errors, even with error_reporting(0)

error-reportingini-setphp

What are some reasons why PHP would force errors to show, no matter what you tell it to disable?

I have tried

error_reporting(0);
ini_set('display_errors', 0);

with no luck.

Best Solution

Note the caveat in the manual at http://uk.php.net/error_reporting:

Most of E_STRICT errors are evaluated at the compile time thus such errors are not reported in the file where error_reporting is enhanced to include E_STRICT errors (and vice versa).

If your underlying system is configured to report E_STRICT errors, these may be output before your code is even considered. Don't forget, error_reporting/ini_set are runtime evaluations, and anything performed in a "before-run" phase will not see their effects.

Based on your comment that your error is...

Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /usr/home/REDACTED/public_html/dev.php on line 11

Then the same general concept applies. Your code is never run, as it is syntactically invalid (you forgot a ';'). Therefore, your change of error reporting is never encountered.

Fixing this requires a change of the system level error reporting. For example, on Apache you may be able to place...

php_value error_reporting 0

in a .htaccess file to suppress them all, but this is system configuration dependent.

Pragmatically, don't write files with syntax errors :)

Related Solutions

Php – How to get PHP errors to display

This always works for me:

ini_set('display_errors', '1');
ini_set('display_startup_errors', '1');
error_reporting(E_ALL);

However, this doesn't make PHP to show parse errors - the only way to show those errors is to modify your php.ini with this line:

display_errors = on

(if you don't have access to php.ini, then putting this line in .htaccess might work too):

php_flag display_errors 1

Php – Remove empty array elements

As you're dealing with an array of strings, you can simply use array_filter(), which conveniently handles all this for you:

print_r(array_filter($linksArray));

Keep in mind that if no callback is supplied, all entries of array equal to FALSE (see converting to boolean) will be removed. So if you need to preserve elements that are i.e. exact string '0', you will need a custom callback:

// PHP 7.4 and later
print_r(array_filter($linksArray, fn($value) => !is_null($value) && $value !== ''));

// PHP 5.3 and later
print_r(array_filter($linksArray, function($value) { return !is_null($value) && $value !== ''; }));

// PHP < 5.3
print_r(array_filter($linksArray, create_function('$value', 'return $value !== "";')));

Best Solution

Related Solutions

Php – How to get PHP errors to display

Php – Remove empty array elements

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