Python – Django: Access primary key in models.filefield(upload_to) location

djangofile-iopython

I'd like to save my files using the primary key of the entry.

Here is my code:

def get_nzb_filename(instance, filename):
    if not instance.pk:
        instance.save() # Does not work.
    name_slug = re.sub('[^a-zA-Z0-9]', '-', instance.name).strip('-').lower()
    name_slug = re.sub('[-]+', '-', name_slug)
    return u'files/%s_%s.nzb' % (instance.pk, name_slug)

class File(models.Model):
    nzb = models.FileField(upload_to=get_nzb_filename)
    name = models.CharField(max_length=256)

I know the first time an object is saved the primary key isn't available, so I'm willing to take the extra hit to save the object just to get the primary key, and then continue on.

The above code doesn't work. It throws the following error:

maximum recursion depth exceeded while calling a Python object

I'm assuming this is an infinite loop. Calling the save method would call the get_nzb_filename method, which would again call the save method, and so on.

I'm using the latest version of the Django trunk.

How can I get the primary key so I can use it to save my uploaded files?

Update @muhuk:

I like your solution. Can you help me implement it? I've updated my code to the following and the error is 'File' object has no attribute 'create'. Perhaps I'm using what you've written out of context?

def create_with_pk(self):
    instance = self.create()
    instance.save()
    return instance

def get_nzb_filename(instance, filename):
    if not instance.pk:
        create_with_pk(instance)
    name_slug = re.sub('[^a-zA-Z0-9]', '-', instance.name).strip('-').lower()
    name_slug = re.sub('[-]+', '-', name_slug)
    return u'files/%s_%s.nzb' % (instance.pk, name_slug)

class File(models.Model):
    nzb = models.FileField(upload_to=get_nzb_filename, blank=True, null=True)
    name = models.CharField(max_length=256)

Instead of enforcing the required field in my model I'll do it in my Form class. No problem.

Best Solution

You can do this by setting upload_to to a temporary location and by creating a custom save method.

The save method should call super first, to generate the primary key (this will save the file to the temporary location). Then you can rename the file using the primary key and move it to it's proper location. Call super one more time to save the changes and you are good to go! This worked well for me when I came across this exact issue.

For example:

class File( models.Model ):
    nzb = models.FileField( upload_to='temp' )

    def save( self, *args, **kwargs ):
        # Call save first, to create a primary key
        super( File, self ).save( *args, **kwargs )

        nzb = self.nzb
        if nzb:
            # Create new filename, using primary key and file extension
            oldfile = self.nzb.name
            dot = oldfile.rfind( '.' )
            newfile = str( self.pk ) + oldfile[dot:]

            # Create new file and remove old one
            if newfile != oldfile:
                self.nzb.storage.delete( newfile )
                self.nzb.storage.save( newfile, nzb )
                self.nzb.name = newfile 
                self.nzb.close()
                self.nzb.storage.delete( oldfile )

        # Save again to keep changes
        super( File, self ).save( *args, **kwargs )
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