Python – Fastest way to check if a value exists in a list

listperformancepython

What is the fastest way to know if a value exists in a list (a list with millions of values in it) and what its index is?

I know that all values in the list are unique as in this example.

The first method I try is (3.8 sec in my real code):

``````a = [4,2,3,1,5,6]

if a.count(7) == 1:
b=a.index(7)
"Do something with variable b"
``````

The second method I try is (2x faster: 1.9 sec for my real code):

``````a = [4,2,3,1,5,6]

try:
b=a.index(7)
except ValueError:
"Do nothing"
else:
"Do something with variable b"
``````

Proposed methods from Stack Overflow user (2.74 sec for my real code):

``````a = [4,2,3,1,5,6]
if 7 in a:
a.index(7)
``````

In my real code, the first method takes 3.81 sec and the second method takes 1.88 sec.
It's a good improvement, but:

I'm a beginner with Python/scripting, and is there a faster way to do the same things and save more processing time?

More specific explanation for my application:

In the Blender API I can access a list of particles:

``````particles = [1, 2, 3, 4, etc.]
``````

From there, I can access a particle's location:

``````particles[x].location = [x,y,z]
``````

And for each particle I test if a neighbour exists by searching each particle location like so:

``````if [x+1,y,z] in particles.location
"Find the identity of this neighbour particle in x:the particle's index
in the array"
particles.index([x+1,y,z])
``````

Best Solution

``````7 in a
``````

Clearest and fastest way to do it.

You can also consider using a `set`, but constructing that set from your list may take more time than faster membership testing will save. The only way to be certain is to benchmark well. (this also depends on what operations you require)