Powershell – Capture EXE output in PowerShell


A little background first.

I've been tasked with encrypting files with a Powershell script using GPG (gnupg.org). The specific exe I'm calling is simply gpg.exe. I'd like to capture the output whenever I execute a command.

For instance, I import a public key in powershell as follows:

& $gpgLocation --import "key.txt"

$gpgLocation is simply the file location of gpg.exe (default being "C:\Program Files\GNU\GnuPG\gpg.exe"

My entire issue here is that if I try:

& $gpgLocation --import "key.txt" | out-file gpgout.txt

All I get is a 1kb file, named appropriately, but it is COMPLETELY blank. I've tried several flags for out-file just to see if I was running into a quirk.

I've also tried sending the command to this code (and capturing the output with the usual out-file etc):

    [string] $processname, 
    [string] $arguments

$processStartInfo = New-Object System.Diagnostics.ProcessStartInfo;
$processStartInfo.FileName = $processname;
$processStartInfo.WorkingDirectory = (Get-Location).Path;
if($arguments) { $processStartInfo.Arguments = $arguments }
$processStartInfo.UseShellExecute = $false;
$processStartInfo.RedirectStandardOutput = $true;

$process = [System.Diagnostics.Process]::Start($processStartInfo);

Any ideas? I'm desperate!

Best Solution

Does the output you're expecting go to standard-error or standard-out?

does this work?

& $gpgLocation --import "key.txt" 2>&1 | out-file gpgout.txt