You can use the order()
function directly without resorting to add-on tools -- see this simpler answer which uses a trick right from the top of the example(order)
code:
R> dd[with(dd, order(-z, b)), ]
b x y z
4 Low C 9 2
2 Med D 3 1
1 Hi A 8 1
3 Hi A 9 1
Edit some 2+ years later: It was just asked how to do this by column index. The answer is to simply pass the desired sorting column(s) to the order()
function:
R> dd[order(-dd[,4], dd[,1]), ]
b x y z
4 Low C 9 2
2 Med D 3 1
1 Hi A 8 1
3 Hi A 9 1
R>
rather than using the name of the column (and with()
for easier/more direct access).
By using the merge
function and its optional parameters:
Inner join: merge(df1, df2)
will work for these examples because R automatically joins the frames by common variable names, but you would most likely want to specify merge(df1, df2, by = "CustomerId")
to make sure that you were matching on only the fields you desired. You can also use the by.x
and by.y
parameters if the matching variables have different names in the different data frames.
Outer join: merge(x = df1, y = df2, by = "CustomerId", all = TRUE)
Left outer: merge(x = df1, y = df2, by = "CustomerId", all.x = TRUE)
Right outer: merge(x = df1, y = df2, by = "CustomerId", all.y = TRUE)
Cross join: merge(x = df1, y = df2, by = NULL)
Just as with the inner join, you would probably want to explicitly pass "CustomerId" to R as the matching variable. I think it's almost always best to explicitly state the identifiers on which you want to merge; it's safer if the input data.frames change unexpectedly and easier to read later on.
You can merge on multiple columns by giving by
a vector, e.g., by = c("CustomerId", "OrderId")
.
If the column names to merge on are not the same, you can specify, e.g., by.x = "CustomerId_in_df1", by.y = "CustomerId_in_df2"
where CustomerId_in_df1
is the name of the column in the first data frame and CustomerId_in_df2
is the name of the column in the second data frame. (These can also be vectors if you need to merge on multiple columns.)
Best Solution
Here are some options:
a$Numbers <- a$Numbers * b
transform(a, Numbers=Numbers * b)
within(a, Numbers <- Numbers * 10
In all cases you need to modify the data frame. The first method is the most direct, but the other two do similar things. For the second and third, you will need to save the result for it to be re-usable elsewhere (e.g.
a <- transform(a, ...)
).