For BSD or GNU grep
you can use -B num
to set how many lines before the match and -A num
for the number of lines after the match.
grep -B 3 -A 2 foo README.txt
If you want the same number of lines before and after you can use -C num
.
grep -C 3 foo README.txt
This will show 3 lines before and 3 lines after.
Use the shell globbing syntax:
grep pattern -r --include=\*.cpp --include=\*.h rootdir
The syntax for --exclude
is identical.
Note that the star is escaped with a backslash to prevent it from being expanded by the shell (quoting it, such as --include="*.cpp"
, would work just as well). Otherwise, if you had any files in the current working directory that matched the pattern, the command line would expand to something like grep pattern -r --include=foo.cpp --include=bar.cpp rootdir
, which would only search files named foo.cpp
and bar.cpp
, which is quite likely not what you wanted.
Update 2021-03-04
I've edited the original answer to remove the use of brace expansion, which is a feature provided by several shells such as Bash and zsh to simplify patterns like this; but note that brace expansion is not POSIX shell-compliant.
The original example was:
grep pattern -r --include=\*.{cpp,h} rootdir
to search through all .cpp
and .h
files rooted in the directory rootdir
.
Best Answer
You can do it using
-v
(for--invert-match
) option of grep as:grep -v "unwanted_word" file
will filter the lines that have theunwanted_word
andgrep XXXXXXXX
will list only lines with patternXXXXXXXX
.EDIT:
From your comment it looks like you want to list all lines without the
unwanted_word
. In that case all you need is: