Ruby – How to pass arguments to define_method

(0...8).map { (65 + rand(26)).chr }.join

I spend too much time golfing.

(0...50).map { ('a'..'z').to_a[rand(26)] }.join

And a last one that's even more confusing, but more flexible and wastes fewer cycles:

o = [('a'..'z'), ('A'..'Z')].map(&:to_a).flatten
string = (0...50).map { o[rand(o.length)] }.join

If you want to generate some random text then use the following:

50.times.map { (0...(rand(10))).map { ('a'..'z').to_a[rand(26)] }.join }.join(" ")

this code generates 50 random word string with words length less than 10 characters and then join with space

define_method is a (private) method of the object Class. You are calling it from an instance. There is no instance method called define_method, so it recurses to your method_missing, this time with :define_method (the name of the missing method), and :screech (the sole argument you passed to define_method).

Try this instead (to define the new method on all Monkey objects):

def method_missing(m)
    puts "No #{m}, so I'll make one..."
    self.class.send(:define_method, :screech) do
      puts "This is the new screech."
    end
end

Or this (to define it only on the object it is called upon, using the object's "eigenclass"):

def method_missing(m)
    puts "No #{m}, so I'll make one..."
    class << self
      define_method(:screech) do
        puts "This is the new screech."
      end
    end
end