N algorithm for calculating the multiplicative order of x modulo y (for y < 1000) that doesn't require a BigInteger type

algorithmdiscrete-mathematicsmath

The algorithm I'm using at the moment runs into extremely high numbers very quickly. A step in the algorithm I'm to raises x to the result of the totient function applied to y. The result is that you can run into very large numbers.

Eg. When calculating the multiplicative order of 10 modulo 53:

10^totient(53) == 10^52 == 1 * 10^52

The following algorithm fares a bit better either in terms of avoiding large numbers, but it still fails where 10^mOrder is greater than the capacity of the data type:

  mOrder = 1
  while 10^mOrder % 53 != 1
      if mOrder >= i
          mOrder = 0;
          break
      else
          mOrder = mOrder + 1

Best Answer

Using Modular exponentiation, it is possible to calculate (10 ^ mOrder % 53) or in general, any (a ^ b mod c) without getting values much bigger than c. See Wikipedia for details, there's this sample code, too:

Bignum modpow(Bignum base, Bignum exponent, Bignum modulus) {

    Bignum result = 1;

    while (exponent > 0) {
        if ((exponent & 1) == 1) {
            // multiply in this bit's contribution while using modulus to keep result small
            result = (result * base) % modulus;
        }
        // move to the next bit of the exponent, square (and mod) the base accordingly
        exponent >>= 1;
        base = (base * base) % modulus;
    }

    return result;
}
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