# R – Ordering Merged data frames

r

As a fairly new R programmer I seem to have run into a strange problem – probably my inexperience with R

After reading and merging successive files into a single data frame, I find that order does not sort the data as expected.

I have multiple references in each file but each file refers to measurement data obtained at a different time.

Here's the code

``````library(reshape)
# Enter file name to Read & Save data
# Find first occurance of file
for ( round1 in 1 : 6) {
break
}

for ( round2 in (round1+1) : 6) {
#
if (round2 == (round1 +1))
z=data.frame(merge(x,y,all=TRUE))
z=data.frame(merge(y,z,all=TRUE))
}
}
ordered = order(z\$lab_id)

results = z[ordered,]

res = data.frame( lab=results[,"lab_id"],bw=results[,"ZBW"],wi=results[,"ZWI"],pf_zbw=0,pf_zwi=0,r = results[,"rnd"])

#
# Establish no of samples recorded
nsmpls = length(res[,c("lab")])

# Evaluate Z_scores for Between Lab Results
for ( i in 1 : nsmpls) {
if (res[i,"bw"] > 3 | res[i,"bw"] < -3)
res[i,"pf_zbw"]=1
}
# Evaluate Z_scores for Within Lab Results
for ( i in 1 : nsmpls) {
if (res[i,"wi"] > 3 | res[i,"wi"] < -3)
res[i,"pf_zwi"]=1
}

dd = melt(res, id=c("lab","r"), "pf_zbw")
b = cast(dd, lab ~ r)
``````

If anyone could see why the ordering only works for about 55 of 70 records and could steer me in the right direction I would be obliged

Thanks very much

#### Best Solution

Check whether z\$lab_id is a factor (with `is.factor(z\$lab_id)`).

If it is, try

``````z\$lab_id <- as.character(z\$lab_id)
``````

if it is supposed to be a character vector; or

``````z\$lab_id <-    as.numeric(as.character(z\$lab_id))
``````

if it is supposed to be a numeric vector.

Then order it again.