Printf formatting (%d versus %u)

c++formattingpointersprintf

What is difference between %d and %u when printing pointer addresses?

For example:

int a = 5;
// check the memory address
printf("memory address = %d\n", &a); // prints "memory address = -12"
printf("memory address = %u\n", &a); // prints "memory address = 65456"

Best Solution

You can find a list of formatting escapes on this page.

%d is a signed integer, while %u is an unsigned integer. Pointers (when treated as numbers) are usually non-negative.

If you actually want to display a pointer, use the %p format specifier.