Try tail:
tail -n +2 "$FILE"
-n x
: Just print the last x
lines. tail -n 5
would give you the last 5 lines of the input. The +
sign kind of inverts the argument and make tail
print anything but the first x-1
lines. tail -n +1
would print the whole file, tail -n +2
everything but the first line, etc.
GNU tail
is much faster than sed
. tail
is also available on BSD and the -n +2
flag is consistent across both tools. Check the FreeBSD or OS X man pages for more.
The BSD version can be much slower than sed
, though. I wonder how they managed that; tail
should just read a file line by line while sed
does pretty complex operations involving interpreting a script, applying regular expressions and the like.
Note: You may be tempted to use
# THIS WILL GIVE YOU AN EMPTY FILE!
tail -n +2 "$FILE" > "$FILE"
but this will give you an empty file. The reason is that the redirection (>
) happens before tail
is invoked by the shell:
- Shell truncates file
$FILE
- Shell creates a new process for
tail
- Shell redirects stdout of the
tail
process to $FILE
tail
reads from the now empty $FILE
If you want to remove the first line inside the file, you should use:
tail -n +2 "$FILE" > "$FILE.tmp" && mv "$FILE.tmp" "$FILE"
The &&
will make sure that the file doesn't get overwritten when there is a problem.
sed
is intended to be used on line-based input. Although it can do what you need.
A better option here is to use the tr
command as follows:
tr '\n' ' ' < input_filename
or remove the newline characters entirely:
tr -d '\n' < input.txt > output.txt
or if you have the GNU version (with its long options)
tr --delete '\n' < input.txt > output.txt
Best Answer
Assuming UTF-8 XML documents:
If you want to encode the bad bytes instead,
You can call it a few different ways: