Short & Snazzy:
+ new Date()
A unary operator like plus
triggers the valueOf
method in the Date
object and it returns the timestamp (without any alteration).
Details:
On almost all current browsers you can use Date.now()
to get the UTC timestamp in milliseconds; a notable exception to this is IE8 and earlier (see compatibility table).
You can easily make a shim for this, though:
if (!Date.now) {
Date.now = function() { return new Date().getTime(); }
}
To get the timestamp in seconds, you can use:
Math.floor(Date.now() / 1000)
Or alternatively you could use:
Date.now() / 1000 | 0
Which should be slightly faster, but also less readable.
(also see this answer or this with further explaination to bitwise operators).
I would recommend using Date.now()
(with compatibility shim). It's slightly better because it's shorter & doesn't create a new Date
object. However, if you don't want a shim & maximum compatibility, you could use the "old" method to get the timestamp in milliseconds:
new Date().getTime()
Which you can then convert to seconds like this:
Math.round(new Date().getTime()/1000)
And you can also use the valueOf
method which we showed above:
new Date().valueOf()
Timestamp in Milliseconds
var timeStampInMs = window.performance && window.performance.now && window.performance.timing && window.performance.timing.navigationStart ? window.performance.now() + window.performance.timing.navigationStart : Date.now();
console.log(timeStampInMs, Date.now());
For .Net <= 4.0 Use the TimeSpan class.
TimeSpan t = TimeSpan.FromSeconds( secs );
string answer = string.Format("{0:D2}h:{1:D2}m:{2:D2}s:{3:D3}ms",
t.Hours,
t.Minutes,
t.Seconds,
t.Milliseconds);
(As noted by Inder Kumar Rathore) For .NET > 4.0 you can use
TimeSpan time = TimeSpan.FromSeconds(seconds);
//here backslash is must to tell that colon is
//not the part of format, it just a character that we want in output
string str = time .ToString(@"hh\:mm\:ss\:fff");
(From Nick Molyneux) Ensure that seconds is less than TimeSpan.MaxValue.TotalSeconds
to avoid an exception.
Best Solution
Probably the easiest way is: