Unix – How to make expect command in expect program script to wait for exact string matching

expectscriptingshshellunix

I want to know how to make expect command in expect script to wait for exact string to be matched before proceeding to next line in the script.

Bourne shell (sh) script:

#!/bin/sh
#!/usr/bin/expect

spawn ssh -Y localuser@lbblr-tirumala
expect -exact "localuser@lbblr-tirumala's password: "

# replace password with ur own passwd
send "geomax45\r"

# replace the prompt with ur own prompt
expect "localuser@lbblr-tirumala:~$ "

# run application
send "./sample\r"

expect "*Menu*\r
1. print hello world\r
2. print Bye world\r
3. quit\r
enter choice: "
# enter choice 1
send "1\r"
expect "Bye world\r
*Menu*\r
1. print hello world\r
2. print Bye world\r
3. quit\r
enter choice: $"
# enter choice 2
send "2\r"

In the above code after entering 1 the code should wait for "Bye world\r……" string to occur on the screen. But even though the screen prompts different string altogether, the code is executing the next line and entering option 2, which should not occur as per definition of expect. It should wait until the complete string in expect command matches.

I want to know whether there is any stricter command that can be used so that expect waits until exact string matching occurs. Please help me in this issue

Best Solution

You're already using it earlier in your script: expect -exact. But long matching strings are pretty much guaranteed to cause problems; you should try to cut it down to the shortest unique match, if necessary breaking it into multiple expect commands.

In this case, just based on what you show, the proper command is probably expect -exact "choice:". But inherently it is not possible to determine this without full details of the possible program outputs.

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